What is the sum from k=0 to infinity of (1)^k ?

The sum from k=0 to infinity of (1)^k is diverges

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sum from k=0 to infinity of (1)^k

k = 0 \sum \infty (1)^{k}

diverges

Solution steps

k = 0 \sum \infty 1^{k}

Simplify

= k = 0 \sum \infty 1

Every infinite sum of a non-zero constant diverges

= diverges

\int \frac{1}{2 x ^{3}} d x

f (x) = 3 - (- 27)

y^{^{''}} + 16 y = t sin (4 t)

f (x) = (2 x^{2} - 1)^{2} (3 x^{2})

e^{2 x}

What is the sum from k=0 to infinity of (1)^k ?
The sum from k=0 to infinity of (1)^k is diverges