What is the derivative of 2sin(θ) ?

The derivative of 2sin(θ) is 2cos(θ)

What is the first derivative of 2sin(θ) ?

The first derivative of 2sin(θ) is 2cos(θ)

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derivative of

2 sin (θ)

2 cos (θ)

Solution steps

\frac{d}{d θ} (2 sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= 2 cos (θ)

\frac{\partial}{\partial x} (x^{2} + 2 x y + 2 y^{2} - 8 x + 8 y)

\int_{1}^{\infty} \frac{1}{x ^{2} + 3} d x

y = 3 1.6 x^{2} + 4.9

f (t) = \frac{1}{2} (9 t^{2} + t)^{- 3}

x \to \infty lim (2 1^{x})

What is the derivative of 2sin(θ) ?
The derivative of 2sin(θ) is 2cos(θ)
What is the first derivative of 2sin(θ) ?
The first derivative of 2sin(θ) is 2cos(θ)