What is (\partial)/(\partial y)(cos(12x)sin(2y)) ?

The answer to (\partial)/(\partial y)(cos(12x)sin(2y)) is cos(12x)cos(2y)*2

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(\partial)/(\partial y)(cos(12x)sin(2y))

\frac{\partial}{\partial y} (cos (12 x) sin (2 y))

cos (12 x) cos (2 y) \cdot 2

Solution steps

\frac{\partial}{\partial y} (cos (12 x) sin (2 y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (12 x) \frac{\partial}{\partial y} (sin (2 y))

Apply the chain rule:

cos (2 y) \frac{\partial}{\partial y} (2 y)

= cos (2 y) \frac{\partial}{\partial y} (2 y)

\frac{\partial}{\partial y} (2 y) = 2

= cos (12 x) cos (2 y) \cdot 2

\int \frac{9}{x ln ( 3 x )} d x

f (x) = - 247

\int \frac{1}{121 + x ^{2}} d x

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\int \frac{2}{sin ( x )} d x

What is (\partial)/(\partial y)(cos(12x)sin(2y)) ?
The answer to (\partial)/(\partial y)(cos(12x)sin(2y)) is cos(12x)cos(2y)*2