What is (\partial)/(\partial x)(y^3-3x^2y) ?

The answer to (\partial)/(\partial x)(y^3-3x^2y) is -6yx

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(\partial)/(\partial x)(y^3-3x^2y)

\frac{\partial}{\partial x} (y^{3} - 3 x^{2} y)

- 6 y x

Solution steps

\frac{\partial}{\partial x} (y^{3} - 3 x^{2} y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{3}) - \frac{\partial}{\partial x} (3 x^{2} y)

\frac{\partial}{\partial x} (y^{3}) = 0

\frac{\partial}{\partial x} (3 x^{2} y) = 6 y x

= 0 - 6 y x

Simplify

= - 6 y x

f (x) = (4 x + 5)^{3} (x^{2} - 6 x + 5)^{4}

\int \frac{36}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

(- 5) (- 5.1)

\frac{d}{d x} (cos^{\frac{7}{4}} (4 x^{3}))

\int_{1}^{8} x + 1 d x

What is (\partial)/(\partial x)(y^3-3x^2y) ?
The answer to (\partial)/(\partial x)(y^3-3x^2y) is -6yx