What is the derivative of (x^2-1/(x^2+1)) ?

The derivative of (x^2-1/(x^2+1)) is (4x)/((x^2+1)^2)

What is the first derivative of (x^2-1/(x^2+1)) ?

The first derivative of (x^2-1/(x^2+1)) is (4x)/((x^2+1)^2)

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\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{2} + 1})

\frac{4 x}{( x ^{2} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{2} + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 1 ) ( x ^{2} + 1 ) - \frac{d}{d x} ( x ^{2} + 1 ) ( x ^{2} - 1 )}{( x ^{2} + 1 ) ^{2}}

\frac{d}{d x} (x^{2} - 1) = 2 x

\frac{d}{d x} (x^{2} + 1) = 2 x

= \frac{2 x ( x ^{2} + 1 ) - 2 x ( x ^{2} - 1 )}{( x ^{2} + 1 ) ^{2}}

Expand

2 x (x^{2} + 1) - 2 x (x^{2} - 1) : 4 x

= \frac{4 x}{( x ^{2} + 1 ) ^{2}}

\int 2 t - 4 d t

f (t) = 2 e^{- t} cos (4 t) 1 (t)

\frac{d y}{d x} = (2 y + 1 cos (x))

\frac{d ^{2}}{d x ^{2}} (x^{3})

\int - \frac{6}{x ^{4}} d x

What is the derivative of (x^2-1/(x^2+1)) ?
The derivative of (x^2-1/(x^2+1)) is (4x)/((x^2+1)^2)
What is the first derivative of (x^2-1/(x^2+1)) ?
The first derivative of (x^2-1/(x^2+1)) is (4x)/((x^2+1)^2)