What is the derivative of x^2-4x+39 ?

The derivative of x^2-4x+39 is 2x-4

What is the first derivative of x^2-4x+39 ?

The first derivative of x^2-4x+39 is 2x-4

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derivative of

x^{2} - 4 x + 39

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x + 39)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (39)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (39) = 0

= 2 x - 4 + 0

Simplify

= 2 x - 4

\int_{1}^{4} π (\frac{1}{x})^{2} d x

y^{^{'}} = 3 x^{2} y

x \to 0 + lim (\frac{ln ( x )}{csc ( x )})

f (x) = \frac{1}{( 1 - x ) ^{2}}

x \to 0 + lim (2 (tan (x))^{x})

What is the derivative of x^2-4x+39 ?
The derivative of x^2-4x+39 is 2x-4
What is the first derivative of x^2-4x+39 ?
The first derivative of x^2-4x+39 is 2x-4