What is the solution for 4y^'+ty=7 ?

The solution for 4y^'+ty=7 is y=(integral of (7e^{\frac{t^2)/8})/(4)}{e^{(t^2)/8}}

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4y^'+ty=7

4 y^{^{'}} + t y = 7

y = \frac{\int \frac{7 e ^{\frac{t ^{2}}{8}}}{4} d t}{e ^{\frac{t ^{2}}{8}}}

Solution steps

4 y^{'} (t) + t y = 7

Solve linear ODE:

y = \frac{\int \frac{7 e ^{\frac{t ^{2}}{8}}}{4} d t}{e ^{\frac{t ^{2}}{8}}}

y = \frac{\int \frac{7 e ^{\frac{t ^{2}}{8}}}{4} d t}{e ^{\frac{t ^{2}}{8}}}

\frac{d ^{2}}{d x ^{2}} (9 - x^{2})

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What is the solution for 4y^'+ty=7 ?
The solution for 4y^'+ty=7 is y=(integral of (7e^{\frac{t^2)/8})/(4)}{e^{(t^2)/8}}