What is the tangent of f(x)= 4/(x+1),\at x=1 ?

The tangent of f(x)= 4/(x+1),\at x=1 is y=-x+3

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tangent of f(x)= 4/(x+1),\at x=1

tangent of

f (x) = \frac{4}{x + 1}, at x = 1

y = - x + 3

Solution steps

Find the tangent point:

(1, 2)

Find the slope of

f (x) = \frac{4}{x + 1} : \frac{df ( x )}{d x} = - \frac{4}{( x + 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

Find the line with slope m=

- 1

and passing through

(1, 2) : y = - x + 3

y = - x + 3

\int \frac{65}{( x - 1 ) ( x ^{2} + 64 )} d x

x \to 25 lim (x - 25)

(x + 1) d y = (x + 6) d x

\frac{\partial}{\partial x} (x^{2} + x)

y^{^{''}} - 2 y^{^{'}} + y = 0, y (0) = 2, y^{^{'}} (0) = 6

What is the tangent of f(x)= 4/(x+1),\at x=1 ?
The tangent of f(x)= 4/(x+1),\at x=1 is y=-x+3