What is the solution for (dy)/(dx)=sin(2x)-ycos(x) ?

The solution for (dy)/(dx)=sin(2x)-ycos(x) is y=2(sin(x)-1)+(c_{1})/(e^{sin(x))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=sin(2x)-ycos(x)

\frac{d y}{d x} = sin (2 x) - y cos (x)

y = 2 (sin (x) - 1) + \frac{c _{1}}{e ^{s i n (x)}}

Solution steps

\frac{d y}{d x} = sin (2 x) - y cos (x)

Solve linear ODE:

y = 2 (sin (x) - 1) + \frac{c _{1}}{e ^{s i n (x)}}

y = 2 (sin (x) - 1) + \frac{c _{1}}{e ^{s i n (x)}}

\frac{d}{d x} (3 x^{4} - 4 x^{3} - 12 x^{2} + 1)

\int \frac{x ^{2} + 4 x + 10}{x ^{3} + 2 x ^{2} + 5 x} d x

\frac{d}{d x} (ln (x (1 - x)))

ln (X^{\frac{1}{2}})

\int \frac{6}{( x + 1 ) ^{2}} d x

What is the solution for (dy)/(dx)=sin(2x)-ycos(x) ?
The solution for (dy)/(dx)=sin(2x)-ycos(x) is y=2(sin(x)-1)+(c_{1})/(e^{sin(x))}