What is laplacetransform t^2+6t-17 ?

The answer to laplacetransform t^2+6t-17 is 2/(s^3)+6/(s^2)-(17)/s

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laplacetransform t^2+6t-17

laplace transform

t^{2} + 6 t - 17

\frac{2}{s ^{3}} + \frac{6}{s ^{2}} - \frac{17}{s}

Solution steps

L {t^{2} + 6 t - 17}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {t^{2}} + 6 L {t} - L {17}

L {t^{2}} : \frac{2}{s ^{3}}

L {t} : \frac{1}{s ^{2}}

L {17} : \frac{17}{s}

= \frac{2}{s ^{3}} + 6 \cdot \frac{1}{s ^{2}} - \frac{17}{s}

Refine

\frac{2}{s ^{3}} + 6 \frac{1}{s ^{2}} - \frac{17}{s} : \frac{2}{s ^{3}} + \frac{6}{s ^{2}} - \frac{17}{s}

= \frac{2}{s ^{3}} + \frac{6}{s ^{2}} - \frac{17}{s}

\frac{\partial}{\partial x} (- \frac{x}{( x + y ) ^{2}})

\int_{0}^{+ oo} x \cdot (x + 1)^{- 2} d x

f (x) = 5 - x

\int_{0}^{3} 1 + x d x

\frac{d}{d x} (\frac{3}{5 x})

What is laplacetransform t^2+6t-17 ?
The answer to laplacetransform t^2+6t-17 is 2/(s^3)+6/(s^2)-(17)/s