What is the d/(dt)(sqrt(2)sin(t)+sqrt(2)) ?

The d/(dt)(sqrt(2)sin(t)+sqrt(2)) is sqrt(2)cos(t)

What is the first d/(dt)(sqrt(2)sin(t)+sqrt(2)) ?

The first d/(dt)(sqrt(2)sin(t)+sqrt(2)) is sqrt(2)cos(t)

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\frac{d}{d t} (2 sin (t) + 2)

2 cos (t)

Solution steps

\frac{d}{d t} (2 sin (t) + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 sin (t)) + \frac{d}{d t} (2)

\frac{d}{d t} (2 sin (t)) = 2 cos (t)

\frac{d}{d t} (2) = 0

= 2 cos (t) + 0

Simplify

= 2 cos (t)

\frac{d}{d x} (e^{0.2 x})

\int x^{4} - 2 x^{3} + 2 d x

\int 16 x^{3} cos (2 - x^{4}) d x

\frac{d}{d u} (cos (u))

y^{^{''}} + 2 y^{^{'}} + y = 0, y (0) = 4, y^{^{'}} (0) = - 3

What is the d/(dt)(sqrt(2)sin(t)+sqrt(2)) ?
The d/(dt)(sqrt(2)sin(t)+sqrt(2)) is sqrt(2)cos(t)
What is the first d/(dt)(sqrt(2)sin(t)+sqrt(2)) ?
The first d/(dt)(sqrt(2)sin(t)+sqrt(2)) is sqrt(2)cos(t)