What is the derivative of 3ax+bx^3 ?

The derivative of 3ax+bx^3 is 3a+3bx^2

What is the first derivative of 3ax+bx^3 ?

The first derivative of 3ax+bx^3 is 3a+3bx^2

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\frac{d}{d x} (3 a x + b x^{3})

3 a + 3 b x^{2}

Solution steps

\frac{d}{d x} (3 a x + b x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 a x) + \frac{d}{d x} (b x^{3})

\frac{d}{d x} (3 a x) = 3 a

\frac{d}{d x} (b x^{3}) = 3 b x^{2}

= 3 a + 3 b x^{2}

\frac{\partial}{\partial x} (3 x^{2} + 5 x y - 7 y^{2} + 1)

\frac{d}{d x} (e^{x^{2} + 4})

\int x^{2} (6 - x^{3}) d x

\frac{d}{d x} (cos^{2} (2 x + 1))

\int \frac{3}{5} d x

What is the derivative of 3ax+bx^3 ?
The derivative of 3ax+bx^3 is 3a+3bx^2
What is the first derivative of 3ax+bx^3 ?
The first derivative of 3ax+bx^3 is 3a+3bx^2