What is the solution for (dx)/(dt)=e^{3t+2x} ?

The solution for (dx)/(dt)=e^{3t+2x} is x=-(ln(-2/3 e^{3t}-c_{1}))/2

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(dx)/(dt)=e^{3t+2x}

\frac{d x}{d t} = e^{3 t + 2 x}

x = - \frac{ln ( - \frac{2}{3} e ^{3 t} - c _{1} )}{2}

Solution steps

\frac{d x}{d t} = e^{3 t + 2 x}

Solve separable ODE:

x = - \frac{ln ( - \frac{2}{3} e ^{3 t} - c _{1} )}{2}

x = - \frac{ln ( - \frac{2}{3} e ^{3 t} - c _{1} )}{2}

\frac{d}{d x} (- \frac{1}{3} ln (\frac{tan ( \frac{x}{2} ) - 3}{3}))

y^{^{''}} + 6 y^{^{'}} + 8 y = 130 cos (3 t)

x \to - \frac{1}{e} lim (x ln (e + \frac{1}{x}))

\int x 1 - 2 x d x

\frac{\partial}{\partial x} (\frac{x}{e ^{\frac{x}{y}}})

What is the solution for (dx)/(dt)=e^{3t+2x} ?
The solution for (dx)/(dt)=e^{3t+2x} is x=-(ln(-2/3 e^{3t}-c_{1}))/2