What is the derivative of-2/((6x-7x^4^3)) ?

The derivative of-2/((6x-7x^4^3)) is (6(6-28x^3))/((6x-7x^4)^4)

What is the first derivative of-2/((6x-7x^4^3)) ?

The first derivative of-2/((6x-7x^4^3)) is (6(6-28x^3))/((6x-7x^4)^4)

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\frac{d}{d x} (- \frac{2}{( 6 x - 7 x ^{4} ) ^{3}})

\frac{6 ( 6 - 28 x ^{3} )}{( 6 x - 7 x ^{4} ) ^{4}}

Solution steps

\frac{d}{d x} (- \frac{2}{( 6 x - 7 x ^{4} ) ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (\frac{1}{( 6 x - 7 x ^{4} ) ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 2 \frac{d}{d x} ((6 x - 7 x^{4})^{- 3})

Apply the chain rule:

- \frac{3}{( 6 x - 7 x ^{4} ) ^{4}} \frac{d}{d x} (6 x - 7 x^{4})

= - \frac{3}{( 6 x - 7 x ^{4} ) ^{4}} \frac{d}{d x} (6 x - 7 x^{4})

\frac{d}{d x} (6 x - 7 x^{4}) = 6 - 28 x^{3}

= - 2 (- \frac{3}{( 6 x - 7 x ^{4} ) ^{4}} (6 - 28 x^{3}))

Simplify

- 2 (- \frac{3}{( 6 x - 7 x ^{4} ) ^{4}} (6 - 28 x^{3})) : \frac{6 ( 6 - 28 x ^{3} )}{( 6 x - 7 x ^{4} ) ^{4}}

= \frac{6 ( 6 - 28 x ^{3} )}{( 6 x - 7 x ^{4} ) ^{4}}

\frac{d y}{d x} = lo g_{10} (x)

\frac{d y}{d x} = \frac{x ^{9} - 8 y}{x}

\frac{d}{d x} (∣ 4 x - 20 ∣)

\int_{6}^{12} 2 x - 18 d x

\int (5 x + 2)^{3} d x

What is the derivative of-2/((6x-7x^4^3)) ?
The derivative of-2/((6x-7x^4^3)) is (6(6-28x^3))/((6x-7x^4)^4)
What is the first derivative of-2/((6x-7x^4^3)) ?
The first derivative of-2/((6x-7x^4^3)) is (6(6-28x^3))/((6x-7x^4)^4)