What is area y=x^2,y=8-x^2,y=4x+11 ?

The answer to area y=x^2,y=8-x^2,y=4x+11 is No Solution

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area y=x^2,y=8-x^2,y=4x+11

area

y = x^{2}, y = 8 - x^{2}, y = 4 x + 11

No Solution

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x^{2} = 8 - x^{2} : x = 2, x = - 2

x^{2} = 4 x + 11 : x = 2 + 15, x = 2 - 15

8 - x^{2} = 4 x + 11 : x = - 3, x = - 1

Curves not bounded

= No Solution

x \to 3 lim ((x - 2)^{2})

\frac{d y}{d x} = \frac{k}{x ^{2}}

\int_{1}^{2} \frac{3 ln ( x )}{x ^{2}} d x

\frac{\partial}{\partial x} (2 y^{2} - 3 x^{2} - z)

\frac{d}{d x} (lo g_{e} (x^{2} + 1))

What is area y=x^2,y=8-x^2,y=4x+11 ?
The answer to area y=x^2,y=8-x^2,y=4x+11 is No Solution