What is the derivative of y=(tan(-1(3x)))2 ?

The derivative of y=(tan(-1(3x)))2 is -6sec^2(3x)

What is the first derivative of y=(tan(-1(3x)))2 ?

The first derivative of y=(tan(-1(3x)))2 is -6sec^2(3x)

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derivative of

y = (tan (- 1 (3 x))) 2

- 6 sec^{2} (3 x)

Solution steps

\frac{d}{d x} (tan (- 1 \cdot 3 x) \cdot 2)

Simplify

tan (- 1 \cdot 3 x) \cdot 2 : - 2 tan (3 x)

= \frac{d}{d x} (- 2 tan (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (tan (3 x))

Apply the chain rule:

sec^{2} (3 x) \frac{d}{d x} (3 x)

= sec^{2} (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 2 sec^{2} (3 x) \cdot 3

Simplify

= - 6 sec^{2} (3 x)

x x

- 0.6 t^{2} + 30 t

\int_{0}^{5} π (- \frac{3}{5} x + 3)^{2} d x

\frac{t ^{3} + 3 t}{t ^{2} - 4 t + 3}

\int \frac{7}{x ( x - 7 ) ^{2}} d x

What is the derivative of y=(tan(-1(3x)))2 ?
The derivative of y=(tan(-1(3x)))2 is -6sec^2(3x)
What is the first derivative of y=(tan(-1(3x)))2 ?
The first derivative of y=(tan(-1(3x)))2 is -6sec^2(3x)