What is the derivative of g(x)=sqrt(8-x) ?

The derivative of g(x)=sqrt(8-x) is -1/(2sqrt(8-x))

What is the first derivative of g(x)=sqrt(8-x) ?

The first derivative of g(x)=sqrt(8-x) is -1/(2sqrt(8-x))

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derivative of

g (x) = 8 - x

- \frac{1}{2 8 - x}

Solution steps

\frac{d}{d x} (8 - x)

Apply the chain rule:

\frac{1}{2 8 - x} \frac{d}{d x} (8 - x)

= \frac{1}{2 8 - x} \frac{d}{d x} (8 - x)

\frac{d}{d x} (8 - x) = - 1

= \frac{1}{2 8 - x} (- 1)

Simplify

= - \frac{1}{2 8 - x}

f (x) = (5 x - 1)^{- \frac{1}{6}}, at x = 13

x \to 0 + lim ((\frac{1}{x})^{3 x})

y = 2 x^{2} + x, (1, 2)

\int_{5}^{2} x d x

y^{^{'}} + 10 y = 10

What is the derivative of g(x)=sqrt(8-x) ?
The derivative of g(x)=sqrt(8-x) is -1/(2sqrt(8-x))
What is the first derivative of g(x)=sqrt(8-x) ?
The first derivative of g(x)=sqrt(8-x) is -1/(2sqrt(8-x))