What is (\partial)/(\partial y)(sin(x^2)-y) ?

The answer to (\partial)/(\partial y)(sin(x^2)-y) is -1

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(\partial)/(\partial y)(sin(x^2)-y)

\frac{\partial}{\partial y} (sin (x^{2}) - y)

- 1

Solution steps

\frac{\partial}{\partial y} (sin (x^{2}) - y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (sin (x^{2})) - \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (sin (x^{2})) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 - 1

Simplify

= - 1

\frac{d}{d x} (2 sin (x))

arcsin (\frac{2}{3})

y^{^{'}} + 6 x^{5} y = x^{5}

y^{^{''}} - y^{^{'}} = e^{t} cos (t)

\int \frac{1}{e ^{x} - e ^{- x}} d x

What is (\partial)/(\partial y)(sin(x^2)-y) ?
The answer to (\partial)/(\partial y)(sin(x^2)-y) is -1