What is the integral from 0 to 2 of 8x ?

The integral from 0 to 2 of 8x is 16

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integral from 0 to 2 of 8x

\int_{0}^{2} 8 x d x

16

Solution steps

\int_{0}^{2} 8 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{0}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{2}

= 8 [\frac{x ^{2}}{2}]_{0}^{2}

Compute the boundaries:

2

= 8 \cdot 2

Simplify

= 16

\int_{2}^{3} x (x - 2) (x + 2) d x

x^{2} - 10 x + 4, (0)

\int \frac{1}{x ^{2} - 10 x + 34} d x

1 - 7 x^{2} y^{^{'}} = x

x \to 8 + lim (\frac{1}{x - 8})