What is the first derivative of 2x-9 ?

The first derivative of 2x-9 is 2

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derivative of 2x-9

\frac{d}{d x} (2 x - 9)

2

Solution steps

\frac{d}{d x} (2 x - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (9)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (9) = 0

= 2 - 0

Simplify

= 2

x \to 0 lim (4^{x})

\frac{s - 5}{( s ^{2} - 6 s + 25 )}

x^{4} - 4 x^{3} - 2, at x = 1

f (x) = 2 x e^{4 x}

n = 0 \sum \infty \frac{n ( n + 1 )}{2}