What is the tangent of f(x)=34x-16x^2,\at x=1 ?

The tangent of f(x)=34x-16x^2,\at x=1 is y=2x+16

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tangent of f(x)=34x-16x^2,\at x=1

tangent of

f (x) = 34 x - 16 x^{2}, at x = 1

y = 2 x + 16

Solution steps

Find the tangent point:

(1, 18)

Find the slope of

f (x) = 34 x - 16 x^{2} : \frac{df ( x )}{d x} = 34 - 32 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(1, 18) : y = 2 x + 16

y = 2 x + 16

10 e^{10 x}

\frac{\partial}{\partial m} (\frac{G ( m , r ) m}{r ^{2}})

x \to 0 - lim (x \cdot e^{\frac{1}{x}})

\frac{1 - 6 t}{4 + t}

\frac{d}{d x} (4 cot (\frac{x}{8}))

What is the tangent of f(x)=34x-16x^2,\at x=1 ?
The tangent of f(x)=34x-16x^2,\at x=1 is y=2x+16