What is the integral from 0 to 1.5 of 1250x ?

The integral from 0 to 1.5 of 1250x is 1406.25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1.5 of 1250x

\int_{0}^{1.5} 1250 x d x

1406.25

Solution steps

\int_{0}^{1.5} 1250 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 1250 \cdot \int_{0}^{1.5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1.5}

= 1250 [\frac{x ^{2}}{2}]_{0}^{1.5}

Simplify

= 1250 [0.5 x^{2}]_{0}^{1.5}

Compute the boundaries:

1.125

= 1250 \cdot 1.125

Simplify

= 1406.25

\int 9 x^{2} + 1 d x

x y^{^{'}} + (3 x + 1) y = e^{(- 3 x)}

- \frac{11}{s ^{5}}

f (x) = 4 x^{3}

\int x \cdot e^{- \frac{x}{2}} d x

What is the integral from 0 to 1.5 of 1250x ?
The integral from 0 to 1.5 of 1250x is 1406.25