What is the integral from 0 to 1 of (35)/(x^5) ?

The integral from 0 to 1 of (35)/(x^5) is diverges

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integral from 0 to 1 of (35)/(x^5)

\int_{0}^{1} \frac{35}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{35}{x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 35 \cdot \int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= 35 [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\int \frac{3}{x ^{2} + 16} d x

x \to 1 lim (\frac{x - 1}{x - 2})

\int \frac{t}{t ^{4} - 4} d t

\int [3 e^{x}]^{4} d x

\frac{\partial}{\partial x} (x^{2} e^{5 x y})

What is the integral from 0 to 1 of (35)/(x^5) ?
The integral from 0 to 1 of (35)/(x^5) is diverges