What is the derivative of x^3-5x ?

The derivative of x^3-5x is 3x^2-5

What is the first derivative of x^3-5x ?

The first derivative of x^3-5x is 3x^2-5

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\frac{d}{d x} (x^{3} - 5 x)

3 x^{2} - 5

Solution steps

\frac{d}{d x} (x^{3} - 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (5 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (5 x) = 5

= 3 x^{2} - 5

\frac{d}{d x} ((1 - x) (x^{2} - 2)^{2})

x \to - 1 + lim (\frac{5}{x + 1})

y = csc (x) (x + cot (x))

f (x) = x^{5} e^{x}

\frac{\partial}{\partial x} (21 x^{3} cos (7 x^{2} y))

What is the derivative of x^3-5x ?
The derivative of x^3-5x is 3x^2-5
What is the first derivative of x^3-5x ?
The first derivative of x^3-5x is 3x^2-5