What is the derivative of f(x)=-4cos(2x) ?

The derivative of f(x)=-4cos(2x) is 8sin(2x)

What is the first derivative of f(x)=-4cos(2x) ?

The first derivative of f(x)=-4cos(2x) is 8sin(2x)

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derivative of

f (x) = - 4 cos (2 x)

8 sin (2 x)

Solution steps

\frac{d}{d x} (- 4 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 4 (- sin (2 x) \cdot 2)

Simplify

= 8 sin (2 x)

\int - \frac{1}{e ^{x}} d x

x \to - 2 lim (1 - x^{2})

\int \frac{x + 2}{x ^{2} + 16} d x

\frac{d}{d x} (\frac{1}{x ^{25}})

(3, - 5), (- 1, 3)

What is the derivative of f(x)=-4cos(2x) ?
The derivative of f(x)=-4cos(2x) is 8sin(2x)
What is the first derivative of f(x)=-4cos(2x) ?
The first derivative of f(x)=-4cos(2x) is 8sin(2x)