What is (\partial)/(\partial x)(e^{-2x^2-5y^2}) ?

The answer to (\partial)/(\partial x)(e^{-2x^2-5y^2}) is -4e^{-2x^2-5y^2}x

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(\partial)/(\partial x)(e^{-2x^2-5y^2})

\frac{\partial}{\partial x} (e^{- 2 x^{2} - 5 y^{2}})

- 4 e^{- 2 x^{2} - 5 y^{2}} x

Solution steps

\frac{\partial}{\partial x} (e^{- 2 x^{2} - 5 y^{2}})

Treat

y

as a constant

Apply the chain rule:

e^{- 2 x^{2} - 5 y^{2}} \frac{\partial}{\partial x} (- 2 x^{2} - 5 y^{2})

= e^{- 2 x^{2} - 5 y^{2}} \frac{\partial}{\partial x} (- 2 x^{2} - 5 y^{2})

\frac{\partial}{\partial x} (- 2 x^{2} - 5 y^{2}) = - 4 x

= e^{- 2 x^{2} - 5 y^{2}} (- 4 x)

Simplify

= - 4 e^{- 2 x^{2} - 5 y^{2}} x

\int x y e^{x} d x

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\frac{\partial}{\partial u} (u^{\frac{1}{3}} \cdot v^{\frac{2}{3}})

\int \frac{1 - x}{x ^{2} + x + 1} d x

4 x^{3} - 5 7 x^{6} + π x

What is (\partial)/(\partial x)(e^{-2x^2-5y^2}) ?
The answer to (\partial)/(\partial x)(e^{-2x^2-5y^2}) is -4e^{-2x^2-5y^2}x