What is the derivative of 2x^2-4x+1 ?

The derivative of 2x^2-4x+1 is 4x-4

What is the first derivative of 2x^2-4x+1 ?

The first derivative of 2x^2-4x+1 is 4x-4

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\frac{d}{d x} (2 x^{2} - 4 x + 1)

4 x - 4

Solution steps

\frac{d}{d x} (2 x^{2} - 4 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 4 x - 4 + 0

Simplify

= 4 x - 4

5 - 3 x

\frac{d}{d x} (\frac{6}{( 1 - x ) ^{4}})

x \to 0 lim (x - tan (x))

f (x) = \frac{x}{6 + x}

f (x) = x in x

What is the derivative of 2x^2-4x+1 ?
The derivative of 2x^2-4x+1 is 4x-4
What is the first derivative of 2x^2-4x+1 ?
The first derivative of 2x^2-4x+1 is 4x-4