What is the integral from 4 to infinity of e^{-5x} ?

The integral from 4 to infinity of e^{-5x} is 1/(5e^{20)}

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integral from 4 to infinity of e^{-5x}

\int_{4}^{\infty} e^{- 5 x} d x

\frac{1}{5 e ^{20}}

Decimal

4.12231 E - 10

Solution steps

\int_{4}^{\infty} e^{- 5 x} d x

Compute the indefinite integral:

\int e^{- 5 x} d x = - \frac{1}{5} e^{- 5 x} + C

Compute the boundaries:

\int_{4}^{\infty} e^{- 5 x} d x = 0 - (- \frac{1}{5 e ^{20}})

= 0 - (- \frac{1}{5 e ^{20}})

Simplify

= \frac{1}{5 e ^{20}}

\frac{d y}{d x} = \frac{e ^{x}}{1 + e ^{x}}

y^{^{''}} + 8 y^{^{'}} + 17 y = 0, y (0) = 1, y^{^{'}} (0) = 0

\int \frac{( x + 2 ) ^{8}}{2 x} d x

e^{- 5}

\int 3 e^{- 0.1 x} d x

What is the integral from 4 to infinity of e^{-5x} ?
The integral from 4 to infinity of e^{-5x} is 1/(5e^{20)}