What is the sum from n=0 to infinity of (n^n)/(n!) ?

The sum from n=0 to infinity of (n^n)/(n!) is diverges

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sum from n=0 to infinity of (n^n)/(n!)

n = 0 \sum \infty \frac{n ^{n}}{n !}

diverges

Solution steps

n = 0 \sum \infty \frac{n ^{n}}{n !}

Apply Series Ratio Test:

diverges

= diverges

f (x) = \frac{- 2}{2 x - 14}

x \to 1 - lim (\frac{1}{ln ( x )})

y = 9 - 6 x, at x = - 1

\int \frac{x ^{6}}{( x - 2 ) ^{2} ( 1 - x ) ^{5}} d x

\frac{d}{d x} (\frac{2 x ^{2}}{x ^{2} - x})

What is the sum from n=0 to infinity of (n^n)/(n!) ?
The sum from n=0 to infinity of (n^n)/(n!) is diverges