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2y^{''}+7y^'-4y=06y^'-2y=x(y^4),y(0)=-2y^'-y^{(5/3)}=0taylor (x^2)/(x^4+16)taylor (\partial)/(\partial x)(y^8+2x^6+2xy)
Frequently Asked Questions (FAQ)
What is the limit as x approaches-4 of 25 ?
The limit as x approaches-4 of 25 is 25