What is (\partial)/(\partial x)(x^2+xe^2y-y) ?

The answer to (\partial)/(\partial x)(x^2+xe^2y-y) is 2x+e^2y

Popular >

(\partial)/(\partial x)(x^2+xe^2y-y)

\frac{\partial}{\partial x} (x^{2} + x e^{2} y - y)

2 x + e^{2} y

Solution steps

\frac{\partial}{\partial x} (x^{2} + x e^{2} y - y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (x e^{2} y) - \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x e^{2} y) = e^{2} y

\frac{\partial}{\partial x} (y) = 0

= 2 x + e^{2} y - 0

Simplify

= 2 x + e^{2} y

\frac{d}{d x} (\frac{( x + 1 ) ^{5}}{( 1 - x ) ^{4}})

y = ln (e^{3 x})

x \to 49 lim (\frac{x ^{2}}{7} - \frac{7}{x})

\frac{\partial}{\partial y} (\frac{x + y}{2})

ln (256 sin^{2} (x))

What is (\partial)/(\partial x)(x^2+xe^2y-y) ?
The answer to (\partial)/(\partial x)(x^2+xe^2y-y) is 2x+e^2y