What is the derivative of e^{2x-1} ?

The derivative of e^{2x-1} is e^{2x-1}*2

What is the first derivative of e^{2x-1} ?

The first derivative of e^{2x-1} is e^{2x-1}*2

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\frac{d}{d x} (e^{2 x - 1})

e^{2 x - 1} \cdot 2

Solution steps

\frac{d}{d x} (e^{2 x - 1})

Apply the chain rule:

e^{2 x - 1} \frac{d}{d x} (2 x - 1)

= e^{2 x - 1} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= e^{2 x - 1} \cdot 2

\int \frac{3 x ^{2} - 8 x + 1}{x ^{3} - 4 x ^{2} + x + 6} d x

\int sin (2 x) sin (4 x) sin (6 x) d x

\int \frac{x ^{\frac{3}{2}} - 2 x ^{6} - 1.2}{x} d x

\int \frac{x ^{2} - x + 2}{x ^{3} + x} d x

x \to 0 - lim (\frac{14 x ^{4} - 14 x}{x})

What is the derivative of e^{2x-1} ?
The derivative of e^{2x-1} is e^{2x-1}*2
What is the first derivative of e^{2x-1} ?
The first derivative of e^{2x-1} is e^{2x-1}*2