What is (\partial)/(\partial x)(2x^2y^3) ?

The answer to (\partial)/(\partial x)(2x^2y^3) is 4xy^3

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(\partial)/(\partial x)(2x^2y^3)

\frac{\partial}{\partial x} (2 x^{2} y^{3})

4 x y^{3}

Solution steps

\frac{\partial}{\partial x} (2 x^{2} y^{3})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y^{3} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 y^{3} \cdot 2 x^{2 - 1}

Simplify

= 4 x y^{3}

\int 2 (4 x^{2} e^{x^{3}}) d x

x \to 0 + lim (x + ln (x))

n = 1 \sum \infty \frac{n}{9 n ^{2} + 1}

\int \frac{x ^{2} - 100}{x} d x

\frac{d y}{d x} = (y sin (x))

What is (\partial)/(\partial x)(2x^2y^3) ?
The answer to (\partial)/(\partial x)(2x^2y^3) is 4xy^3