What is the first derivative of 2t+1 ?

The first derivative of 2t+1 is 2

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derivative of 2t+1

derivative of

2 t + 1

2

Solution steps

\frac{d}{d t} (2 t + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 t) + \frac{d}{d t} (1)

\frac{d}{d t} (2 t) = 2

\frac{d}{d t} (1) = 0

= 2 + 0

Simplify

= 2

x^{2} + 6, 7 x^{2}

\frac{d}{d x} ((x^{2} + y^{2} + z^{2})^{\frac{3}{2}})

x^{4} + 4

\frac{\partial}{\partial x} (e^{x^{2} + x y})

y^{^{''}} - 9 y = 54