What is the tangent of y=x^2-3x-3,(2,-5) ?

The tangent of y=x^2-3x-3,(2,-5) is y=x-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=x^2-3x-3,(2,-5)

tangent of

y = x^{2} - 3 x - 3, (2, - 5)

y = x - 7

Solution steps

Find the slope of

y = x^{2} - 3 x - 3 : \frac{d y}{d x} = 2 x - 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(2, - 5) : y = x - 7

y = x - 7

(- 5, - 11), (5, 3)

y^{^{'}} = y (2 - y)

\int (- 28 t + 40) d t

x \to 1 - lim (1 - x^{2})

3 sin (x) sin (y) + cos (y) y^{^{'}} = 0

What is the tangent of y=x^2-3x-3,(2,-5) ?
The tangent of y=x^2-3x-3,(2,-5) is y=x-7