What is (\partial)/(\partial x)(cos(x^2)) ?

The answer to (\partial)/(\partial x)(cos(x^2)) is -sin(x^2)*2x

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(\partial)/(\partial x)(cos(x^2))

\frac{\partial}{\partial x} (cos (x^{2}))

- sin (x^{2}) \cdot 2 x

Solution steps

\frac{\partial}{\partial x} (cos (x^{2}))

Apply the chain rule:

- sin (x^{2}) \frac{\partial}{\partial x} (x^{2})

= - sin (x^{2}) \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

= - sin (x^{2}) \cdot 2 x

\int \frac{x ^{2} + 3 x - 2}{x} d x

\int \frac{2 x}{x ^{4} + 1} d x

\int 5 x^{2} a^{2} - x^{2} d x

x \to \frac{π}{6} lim (cot (2 x))

x \frac{d y}{d x} - y = 2020 x^{2}

What is (\partial)/(\partial x)(cos(x^2)) ?
The answer to (\partial)/(\partial x)(cos(x^2)) is -sin(x^2)*2x