What is area 5/x , 5/(x^2)1,7 ?

The answer to area 5/x , 5/(x^2)1,7 is No Solution

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area 5/x , 5/(x^2)1,7

area

\frac{5}{x}, \frac{5}{x ^{2}} 1, 7

No Solution

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{5}{x} = \frac{5}{x ^{2}} \cdot 1 : x = 1

\frac{5}{x} = 7 : x = \frac{5}{7}

\frac{5}{x ^{2}} \cdot 1 = 7 : x = \frac{5}{7}, x = - \frac{5}{7}

Curves not bounded

= No Solution

\int \frac{4 x ^{2} - 3 x + 4}{x ( x ^{2} + 4 )} d x

y = \frac{1}{2} x^{2}, \frac{1}{x ^{2} + 1}

(1 + x) \frac{d y}{d x} - x y = x^{2} + x

\frac{\partial}{\partial y} (3 x^{2} + 2 x y)

\frac{d}{d a} (sin^{3} (a) + cos^{3} (a))

What is area 5/x , 5/(x^2)1,7 ?
The answer to area 5/x , 5/(x^2)1,7 is No Solution