What is the tangent of f(x)= 1/(1-x),\at x=2 ?

The tangent of f(x)= 1/(1-x),\at x=2 is y=x-3

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tangent of f(x)= 1/(1-x),\at x=2

tangent of

f (x) = \frac{1}{1 - x}, at x = 2

y = x - 3

Solution steps

Find the tangent point:

(2, - 1)

Find the slope of

f (x) = \frac{1}{1 - x} : \frac{df ( x )}{d x} = \frac{1}{( 1 - x ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(2, - 1) : y = x - 3

y = x - 3

\frac{d y}{d t} = y - 4 t + (y - 4 t)^{2} + 4

\int x (2 x^{2} + 1)^{5} d x

(- 3, 5), (2, - 1)

x \to - 2 - lim (\frac{3}{x ^{2} - 4})

y^{^{'}} = \frac{( x ^{2} + 2 y ^{2} )}{x y}

What is the tangent of f(x)= 1/(1-x),\at x=2 ?
The tangent of f(x)= 1/(1-x),\at x=2 is y=x-3