What is (\partial)/(\partial x)(3x^2y^2) ?

The answer to (\partial)/(\partial x)(3x^2y^2) is 6xy^2

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(\partial)/(\partial x)(3x^2y^2)

\frac{\partial}{\partial x} (3 x^{2} y^{2})

6 x y^{2}

Solution steps

\frac{\partial}{\partial x} (3 x^{2} y^{2})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 y^{2} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 y^{2} \cdot 2 x^{2 - 1}

Simplify

= 6 x y^{2}

3 t^{2} + 3 t + 1

f (x) = x^{6} \cdot e^{x}

f (x) = \frac{3}{4 x}

(4 x - 5)^{3} (1 - x^{5})^{2}

y^{^{'}} = (x + y)^{2}, y (0) = 1

What is (\partial)/(\partial x)(3x^2y^2) ?
The answer to (\partial)/(\partial x)(3x^2y^2) is 6xy^2