What is laplacetransform sin(x) ?

The answer to laplacetransform sin(x) is 1/(s^2+1)

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laplacetransform sin(x)

laplace transform

sin (x)

\frac{1}{s ^{2} + 1}

Solution steps

L {sin (x)}

Use Laplace Transform table:

L {sin (a t)} = \frac{a}{s ^{2} + a ^{2}}

L {sin (x)} = \frac{1}{s ^{2} + 1 ^{2}}

= \frac{1}{s ^{2} + 1 ^{2}}

= \frac{1}{s ^{2} + 1}

\frac{\partial}{\partial x} (2 + y ln (4 + x (y)^{2}))

\frac{d}{d x} (\frac{x y sin ( x - y )}{1 + x ^{2} + y ^{2}})

f (x) = 3^{s i n (3 x)}

\int \frac{2 + w ^{4}}{w ^{3} + 9 w} d w

\frac{d y}{d x} + \frac{y}{x} = \frac{1}{x}

What is laplacetransform sin(x) ?
The answer to laplacetransform sin(x) is 1/(s^2+1)