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Popular >

y^'-5y=0

Solution

y^{^{'}} - 5 y = 0

Solution

y = e^{5 t + c_{1}}

Solution steps

y^{'} (t) - 5 y = 0

Solve separable ODE:

y = e^{5 t + c_{1}}

y = e^{5 t + c_{1}}

Graph

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n = 1 \sum \infty n^{7} (1 + n^{8})^{0}

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n = 1 \sum \infty - \frac{15}{2} \cdot (\frac{2}{3})^{n}

inverse oflaplace (s^2)/(s^2+1)inverse laplace

\frac{s ^{2}}{s ^{2} + 1}

Frequently Asked Questions (FAQ)

What is the solution for y^'-5y=0 ?
The solution for y^'-5y=0 is y=e^{5t+c_{1}}