What is the sum from n=0 to infinity of ((n-1))/n ?

The sum from n=0 to infinity of ((n-1))/n is diverges

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sum from n=0 to infinity of ((n-1))/n

n = 0 \sum \infty \frac{( n - 1 )}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{n - 1}{n}

Apply Series Divergence Test:

diverges

= diverges

\int_{1}^{3} (x^{2} - 4 x + 3) d x

\frac{d}{d x} (2 x^{2} - 7 x)

\int \frac{x ^{2}}{e ^{7 x}} d x

\int \frac{1}{x ^{2} - 5 x + 6} d x

x \to - 2 lim (\frac{x + 2}{x - 2})

What is the sum from n=0 to infinity of ((n-1))/n ?
The sum from n=0 to infinity of ((n-1))/n is diverges