What is the derivative of 2sin(x-1) ?

The derivative of 2sin(x-1) is 2cos(x)

What is the first derivative of 2sin(x-1) ?

The first derivative of 2sin(x-1) is 2cos(x)

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\frac{d}{d x} (2 sin (x) - 1)

2 cos (x)

Solution steps

\frac{d}{d x} (2 sin (x) - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sin (x)) - \frac{d}{d x} (1)

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

\frac{d}{d x} (1) = 0

= 2 cos (x) - 0

Simplify

= 2 cos (x)

\int (ln (x y)) d x

\frac{d}{d x} (x (a + x)^{2} (a - x)^{3})

18 t^{2} + 9

\frac{d}{d x} (tan (3 x) csc (3 x))

\int 15 (3 x - 7)^{\frac{3}{2}} d x

What is the derivative of 2sin(x-1) ?
The derivative of 2sin(x-1) is 2cos(x)
What is the first derivative of 2sin(x-1) ?
The first derivative of 2sin(x-1) is 2cos(x)