What is the limit as x approaches 0 of (2+sin(x))/x ?

The limit as x approaches 0 of (2+sin(x))/x is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (2+sin(x))/x

x \to 0 lim (\frac{2 + sin ( x )}{x})

diverges

Solution steps

x \to 0 lim (\frac{2 + sin ( x )}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{2 + sin ( x )}{x}) = \infty

x \to 0 - lim (\frac{2 + sin ( x )}{x}) = - \infty

= diverges

\int 2 x + 5 d x

x \frac{d y}{d x} + y = 4 x + 1, y (1) = 8

x \to 6 lim (x - 5)

\int (x + 1) d x

x \to - 2 lim (\frac{x + 1}{x ^{3} + 8})

What is the limit as x approaches 0 of (2+sin(x))/x ?
The limit as x approaches 0 of (2+sin(x))/x is diverges