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Popular >

derivative of (-2cos(2x-sin(3x))^2)

Solution

\frac{d}{d x} ((- 2 cos (2 x) - sin (3 x))^{2})

Solution

2 (- 2 cos (2 x) - sin (3 x)) (4 sin (2 x) - 3 cos (3 x))

Solution steps

\frac{d}{d x} ((- 2 cos (2 x) - sin (3 x))^{2})

Apply the chain rule:

2 (- 2 cos (2 x) - sin (3 x)) \frac{d}{d x} (- 2 cos (2 x) - sin (3 x))

= 2 (- 2 cos (2 x) - sin (3 x)) \frac{d}{d x} (- 2 cos (2 x) - sin (3 x))

\frac{d}{d x} (- 2 cos (2 x) - sin (3 x)) = 4 sin (2 x) - 3 cos (3 x)

= 2 (- 2 cos (2 x) - sin (3 x)) (4 sin (2 x) - 3 cos (3 x))

Graph

Popular Examples

limit as x approaches 4 of (2x^3-128)/(sqrt(x)-2)

x \to 4 lim (\frac{2 x ^{3} - 128}{x - 2})

derivative of 1/(7x^2)

\frac{d}{d x} (\frac{1}{7 x ^{2}})

tangent of x+7/x tangent of

x + \frac{7}{x}

integral of (ln(3x))/(x^2)

\int \frac{ln ( 3 x )}{x ^{2}} d x

derivative of 2e^{2x-1}

\frac{d}{d x} (2 e^{2 x - 1})

Frequently Asked Questions (FAQ)

What is the derivative of (-2cos(2x-sin(3x))^2) ?
The derivative of (-2cos(2x-sin(3x))^2) is 2(-2cos(2x)-sin(3x))(4sin(2x)-3cos(3x))
What is the first derivative of (-2cos(2x-sin(3x))^2) ?
The first derivative of (-2cos(2x-sin(3x))^2) is 2(-2cos(2x)-sin(3x))(4sin(2x)-3cos(3x))