What is the first derivative of 5-3x ?

The first derivative of 5-3x is -3

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derivative of 5-3x

\frac{d}{d x} (5 - 3 x)

- 3

Solution steps

\frac{d}{d x} (5 - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5) - \frac{d}{d x} (3 x)

\frac{d}{d x} (5) = 0

\frac{d}{d x} (3 x) = 3

= 0 - 3

Simplify

= - 3

20 t^{3}

y = sin^{2} (x^{2})

\frac{\partial}{\partial x} (ln (4 x^{2} + y^{2} + 2))

\int \frac{x ^{2}}{2} - \frac{2}{x ^{2}} d x

\frac{d y}{d x} = \frac{( y - 2 )}{( y - 1 )}