What is the derivative of (2x^2^2) ?

The derivative of (2x^2^2) is 16x^3

What is the first derivative of (2x^2^2) ?

The first derivative of (2x^2^2) is 16x^3

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\frac{d}{d x} ((2 x^{2})^{2})

16 x^{3}

Solution steps

\frac{d}{d x} ((2 x^{2})^{2})

Simplify

(2 x^{2})^{2} : 4 x^{4}

= \frac{d}{d x} (4 x^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot 4 x^{4 - 1}

Simplify

= 16 x^{3}

f (x) = \frac{10 x + 8 x ^{2}}{( 5 + 8 x ) ^{2}}

4 x, 2 x

f (x) = 7 e^{x} x

\int sin^{2} (3 x) cos (3 x) d x

\int x^{2} e^{6 x} d x

What is the derivative of (2x^2^2) ?
The derivative of (2x^2^2) is 16x^3
What is the first derivative of (2x^2^2) ?
The first derivative of (2x^2^2) is 16x^3