What is the derivative of x^2+4y^2 ?

The derivative of x^2+4y^2 is 2x

What is the first derivative of x^2+4y^2 ?

The first derivative of x^2+4y^2 is 2x

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derivative of

x^{2} + 4 y^{2}

2 x

Solution steps

\frac{d}{d x} (x^{2} + 4 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 y^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 y^{2}) = 0

= 2 x + 0

Simplify

= 2 x

y^{^{'}} = \frac{( 3 t ^{2} - e ^{t} )}{2 y - 5}

x \to 5 lim (2 e^{x} - 2 ln (x))

\frac{d}{d t} (- 2 t)

\int tan^{2} (1) d x

y = 9 x^{2}, x = 1, y = 0

What is the derivative of x^2+4y^2 ?
The derivative of x^2+4y^2 is 2x
What is the first derivative of x^2+4y^2 ?
The first derivative of x^2+4y^2 is 2x