What is the integral of n/(n^2+6n+10) ?

The integral of n/(n^2+6n+10) is n/(n^2+6n+10)x+C

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integral of n/(n^2+6n+10)

\int \frac{n}{n ^{2} + 6 n + 10}

\frac{n}{n ^{2} + 6 n + 10} x + C

Solution steps

\int \frac{n}{n ^{2} + 6 n + 10} d x

Integral of a constant:

\int a d x = a x

= \frac{n}{n ^{2} + 6 n + 10} x

Add a constant to the solution

= \frac{n}{n ^{2} + 6 n + 10} x + C

\int \frac{4 x - 3}{4 x ^{2} - 6 x} d x

\int \frac{( x + 1 )}{x ^{2} + 2 x} d x

\int tanh (\frac{x}{6}) d x

x \to 0 lim (2 cos (\frac{1}{x}))

3 cos (2 x)

What is the integral of n/(n^2+6n+10) ?
The integral of n/(n^2+6n+10) is n/(n^2+6n+10)x+C