What is the integral from 0 to pi of integral of 1 ?

The integral from 0 to pi of integral of 1 is pi(x+C)

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integral from 0 to pi of integral of 1

\int_{0}^{π} \int 1 d x d y

π (x + C)

Solution steps

\int_{0}^{π} \int 1 d x d y

\int 1 d x = x + C

= \int_{0}^{π} (x + C) d y

\int_{0}^{π} (x + C) d y = π (x + C)

= π (x + C)

x \to \infty lim (x^{- 5})

\frac{d}{d x} (\frac{768}{x} - 1)

\int_{- 1}^{0} 6 \frac{e ^{\frac{1}{x}}}{x ^{3}} d x

12 - x - x^{2}, x + 4

y 1 = x^{3} + 4 x^{2} - 6 x - 9, y 2 = 3 x^{2}

What is the integral from 0 to pi of integral of 1 ?
The integral from 0 to pi of integral of 1 is pi(x+C)